Since $\cos^2t\sin^2t=1$, dividing both sides by $\cos^2 t$ we also have $$1\tan^2t=\frac 1{\cos^2t}$$ Also, in the second quadrant, $\cos t0$ Use the second equation and the restriction to find $\cos t$, then use the first equation and the restriction to find $\sin t$ Then add those for your final answer(III) sin(π 6) = 1 2 cos(2 3 π) =cos(1 3 π) =1 2 tan(π 4) Prove tan(θ / 2) = sin θ / (1 cos θ) for θ in quadrant 1
Determine The Quadrant When The Terminal Side Of The Angle Lies According To The Following Conditions Sin T 0 Tan T 0 Study Com
